-3y^2+105y=0

Solution for -3y^2+105y=0 equation:

-3y^2+105y=0

a = -3; b = 105; c = 0;
Δ = b2-4ac
Δ = 1052-4·(-3)·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-105}{2*-3}=\frac{-210}{-6}
=+35
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+105}{2*-3}=\frac{0}{-6}
=0
$